What is the domain of f(x)= 1/(xsqrt(1+x)) ?

The domain of f(x)= 1/(xsqrt(1+x)) is -1 0

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domain of f(x)= 1/(xsqrt(1+x))

domain

f (x) = \frac{1}{x 1 + x}

- 1 < x < 0 or x > 0

Interval Notation

(- 1, 0) \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 0, x = - 1

Combine real regions and undefined points for final function domain

- 1 < x < 0 or x > 0

x^{2} - 10 ln (x)

f (x) = \frac{x ^{2} - 2}{x ^{2} + 3}

\frac{x ^{2} + 2 x - 3}{x ^{2} - 1}

- 8

f (x) = \frac{x ^{2} - 8 x + 15}{x ^{2} - 7 x + 12}

What is the domain of f(x)= 1/(xsqrt(1+x)) ?
The domain of f(x)= 1/(xsqrt(1+x)) is -1<x<0\lor x>0