What is the domain of f(x)=ln(x^2+x-6)+sqrt(x^2+x-2) ?

The domain of f(x)=ln(x^2+x-6)+sqrt(x^2+x-2) is x 2

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domain of f(x)=ln(x^2+x-6)+sqrt(x^2+x-2)

domain

f (x) = ln (x^{2} + x - 6) + x^{2} + x - 2

x < - 3 or x > 2

Interval Notation

(- \infty, - 3) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 1

Find positive values for logs:

x < - 3 or x > 2

Combine real regions and undefined points for final function domain

x < - 3 or x > 2

f (x) = \frac{x + 5}{x - 4}

f (x) = - 4 x + 16

f (x) = \frac{1}{3 x + 5}

f (x) = 5 (x - 9)^{2} - 32

f (x) = \frac{3 x - 1}{5 - x}

What is the domain of f(x)=ln(x^2+x-6)+sqrt(x^2+x-2) ?
The domain of f(x)=ln(x^2+x-6)+sqrt(x^2+x-2) is x<-3\lor x>2