What is the domain of g(x)= 1/(x(x+2)) ?

The domain of g(x)= 1/(x(x+2)) is x 0

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domain of g(x)= 1/(x(x+2))

domain

g (x) = \frac{1}{x ( x + 2 )}

x < - 2 or - 2 < x < 0 or x > 0

Interval Notation

(- \infty, - 2) \cup (- 2, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 2

The function domain

x < - 2 or - 2 < x < 0 or x > 0

f (x) = (3 x - 3)^{2}

f (x) = 2 + x^{2} - 4 x

f (x) = lo g_{2} (\frac{3 x - 2}{x - 1} + 1)

y = lo g_{10} (5 + 3 x)

f (x) = (2 x)^{\frac{1}{3}} - 7

What is the domain of g(x)= 1/(x(x+2)) ?
The domain of g(x)= 1/(x(x+2)) is x<-2\lor-2<x<0\lor x>0