What is the domain of f(x)= 1/(sqrt(4x-16)) ?

The domain of f(x)= 1/(sqrt(4x-16)) is x>4

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domain of f(x)= 1/(sqrt(4x-16))

domain

f (x) = \frac{1}{4 x - 16}

x > 4

Interval Notation

(4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

x > 4

3 + x

f (x) = (\frac{4}{x}) + 2

f (x) = lo g_{10} (4 x - x^{2})

f (x) = x - 4 - \frac{3}{5 - x}

y = \frac{x ^{2}}{x ^{2} - 9}

What is the domain of f(x)= 1/(sqrt(4x-16)) ?
The domain of f(x)= 1/(sqrt(4x-16)) is x>4