What is the domain of y=(2x)^{1/3}-7 ?

The domain of y=(2x)^{1/3}-7 is -infinity <x<infinity

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domain of y=(2x)^{1/3}-7

domain

y = (2 x)^{\frac{1}{3}} - 7

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{ln ( 5 x )}{x}

f (x) = \frac{x ^{2} + 1}{x ^{2} + 5}

y = x^{2} + 8

y = \frac{6 + x}{3 - x}

f (x) = 3 x + \frac{5}{4}

What is the domain of y=(2x)^{1/3}-7 ?
The domain of y=(2x)^{1/3}-7 is -infinity <x<infinity