What is the domain of 1/(sqrt(4x-1))-sqrt(1-x^2) ?

The domain of 1/(sqrt(4x-1))-sqrt(1-x^2) is 1/4 <x<= 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of 1/(sqrt(4x-1))-sqrt(1-x^2)

domain

\frac{1}{4 x - 1} - 1 - x^{2}

\frac{1}{4} < x \leq 1

Interval Notation

(\frac{1}{4}, 1]

Solution steps

Find non-negative values for radicals:

\frac{1}{4} \leq x \leq 1

Find undefined (singularity) points:

x = \frac{1}{4}

Combine real regions and undefined points for final function domain

\frac{1}{4} < x \leq 1

\frac{x - 2}{x ^{2}}

y = - 2^{x} - 1

∣ x ∣ ∣ x - 1 ∣

\frac{x + 4}{x - 4}

y = x^{3} - 2 x^{2} + 5 x + 7

What is the domain of 1/(sqrt(4x-1))-sqrt(1-x^2) ?
The domain of 1/(sqrt(4x-1))-sqrt(1-x^2) is 1/4 <x<= 1