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Popular >

extreme f(x)=4x^2+16x+17

Solution

extreme points

f (x) = 4 x^{2} + 16 x + 17

Solution

Minimum (- 2, 1)

Solution steps

f^{'} (x) = 8 x + 16

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

4 x^{2} + 16 x + 17 : 1

Minimum (- 2, 1)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=4x^2+16x+17 ?
The extreme f(x)=4x^2+16x+17 is Minimum(-2,1)