What is the domain of 1/(2x+7),-3<= x<= 6 ?

The domain of 1/(2x+7),-3<= x<= 6 is -3<= x<= 6

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domain of 1/(2x+7),-3<= x<= 6

domain

\frac{1}{2 x + 7}, - 3 \leq x \leq 6

- 3 \leq x \leq 6

Interval Notation

[- 3, 6]

Solution steps

Set the domain to the given interval

- 3 \leq x \leq 6

Find undefined (singularity) points:

No real undefined points

Join undefined points with the domain:

(x < - \frac{7}{2} or x > - \frac{7}{2}) and - 3 \leq x \leq 6

- 3 \leq x \leq 6

f (x) = x^{2} + y^{2} = 9

f (x) = 2 π r^{2} + 8 π r

f (x) = \frac{3}{( x ^{2} - x )}

f (x) = \frac{4 x + 3}{x ^{2} - 1}

f (x) = \frac{4 - x ^{2}}{x - 1}

What is the domain of 1/(2x+7),-3<= x<= 6 ?
The domain of 1/(2x+7),-3<= x<= 6 is -3<= x<= 6