What is the domain of f(x)=(sqrt(1-x))/(x^2-1) ?

The domain of f(x)=(sqrt(1-x))/(x^2-1) is x<-1\lor-1<x<1

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domain of f(x)=(sqrt(1-x))/(x^2-1)

domain

f (x) = \frac{1 - x}{x ^{2} - 1}

x < - 1 or - 1 < x < 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1)

Solution steps

Find non-negative values for radicals:

x \leq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or - 1 < x < 1

- x^{2} + x - 2

(\frac{1}{2})^{x} + 3

\frac{x - 3}{x ^{2}}

f (x) = \frac{3}{( x - 5 ) ^{2}}

f (x) = \frac{x - 1}{3 x ^{2} - 75}

What is the domain of f(x)=(sqrt(1-x))/(x^2-1) ?
The domain of f(x)=(sqrt(1-x))/(x^2-1) is x<-1\lor-1<x<1