What is the domain of y= 1/(sqrt(1-x^2)) ?

The domain of y= 1/(sqrt(1-x^2)) is -1<x<1

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domain of y= 1/(sqrt(1-x^2))

domain

y = \frac{1}{1 - x ^{2}}

- 1 < x < 1

Interval Notation

(- 1, 1)

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

- 1 < x < 1

2 x + 9

f (x) = \frac{x + 2}{2 x + 1}

f (x) = (x - 3)^{2} - 5

\frac{3 x - 4}{2 - x}

f (x) = x^{2} - 6 x + 5, 0 \leq x \leq 6

What is the domain of y= 1/(sqrt(1-x^2)) ?
The domain of y= 1/(sqrt(1-x^2)) is -1<x<1