What is the domain of f(x)=sqrt((x-3)/2+x/3) ?

The domain of f(x)=sqrt((x-3)/2+x/3) is x>= 9/5

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domain of f(x)=sqrt((x-3)/2+x/3)

domain

f (x) = \frac{x - 3}{2} + \frac{x}{3}

x \geq \frac{9}{5}

Interval Notation

[\frac{9}{5}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{9}{5}

The function domain

x \geq \frac{9}{5}

f (x) = \frac{x ^{2} - 3}{x ^{2} + 1}

2 cos (x) - 1

x^{2} - 5 x - 6

f (x) = - 2 x^{2} + 8 x - 5

\frac{4}{x + 8}

What is the domain of f(x)=sqrt((x-3)/2+x/3) ?
The domain of f(x)=sqrt((x-3)/2+x/3) is x>= 9/5