What is the domain of f(x)=(x^2+1) ?

The domain of f(x)=(x^2+1) is -infinity <x<infinity

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domain of f(x)=(x^2+1)

domain

f (x) = (x^{2} + 1)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{1}{2 x - x ^{2}}

\frac{3 - x}{x ^{2} - 4}

f (x) = arccos (\frac{x + 1}{2})

x^{3} + (4 x^{2} + 17 x - 15)

f (x) = \frac{x + 5}{x - 6}

What is the domain of f(x)=(x^2+1) ?
The domain of f(x)=(x^2+1) is -infinity <x<infinity