What is the domain of (x-2+|x-1|)/(|x-2|+x-1) ?

The domain of (x-2+|x-1|)/(|x-2|+x-1) is -infinity <x<infinity

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domain of (x-2+|x-1|)/(|x-2|+x-1)

domain

\frac{x - 2 + ∣ x - 1 ∣}{∣ x - 2 ∣ + x - 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find undefined (singularity) points:

No real undefined points

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = cos (arccos (x))

f (x) = \frac{8}{( x - 4 ) ^{2}}

1 - \frac{2}{x}

f (x) = \frac{2 x ^{2} - 3 x}{x ^{2} - x - 12}

f (x) = 35 + 2 e^{- 2 x + 3}

What is the domain of (x-2+|x-1|)/(|x-2|+x-1) ?
The domain of (x-2+|x-1|)/(|x-2|+x-1) is -infinity <x<infinity