What is the domain of f(x)=(1/(sqrt(x)))/(x^2-9) ?

The domain of f(x)=(1/(sqrt(x)))/(x^2-9) is 0 3

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domain of f(x)=(1/(sqrt(x)))/(x^2-9)

domain

f (x) = \frac{\frac{1}{x}}{x ^{2} - 9}

0 < x < 3 or x > 3

Interval Notation

(0, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 3, x = - 3, x = 0

Combine real regions and undefined points for final function domain

0 < x < 3 or x > 3

f (x) = - 4 x + 4

e^{x} + e^{- x}

\frac{x ^{2} + 15}{3}

f (x) = \frac{2 x + 14}{x ^{2} - 49}

f (x) = \frac{5}{x} + \frac{7}{x + 7}

What is the domain of f(x)=(1/(sqrt(x)))/(x^2-9) ?
The domain of f(x)=(1/(sqrt(x)))/(x^2-9) is 0<x<3\lor x>3