What is the domain of f(x)=(x^3+x^2+x+1)/(|x+1|) ?

The domain of f(x)=(x^3+x^2+x+1)/(|x+1|) is x -1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x^3+x^2+x+1)/(|x+1|)

domain

f (x) = \frac{x ^{3} + x ^{2} + x + 1}{∣ x + 1 ∣}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

x^{3} - 3 x^{2} + 1

f (x) = \frac{3 x}{x + 1}

f (x) = \frac{1}{- x ^{2} + 5 x}

f (x) = 2 x - 30

\frac{2}{3} x

What is the domain of f(x)=(x^3+x^2+x+1)/(|x+1|) ?
The domain of f(x)=(x^3+x^2+x+1)/(|x+1|) is x<-1\lor x>-1