What is the domain of ((x+1)^2)/(1+x^2) ?

The domain of ((x+1)^2)/(1+x^2) is -infinity <x<infinity

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domain of ((x+1)^2)/(1+x^2)

domain

\frac{( x + 1 ) ^{2}}{1 + x ^{2}}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{4}{x - 7}

f (x) = lo g_{10} (x)

y = lo g_{10} (1 - 6 x)

f (x) = - x - 4 + 9

f (x) = \frac{4 x - 3}{x}

What is the domain of ((x+1)^2)/(1+x^2) ?
The domain of ((x+1)^2)/(1+x^2) is -infinity <x<infinity