What is the domain of f(x)=(8x^2+12x)/(9x^2-12x+4) ?

The domain of f(x)=(8x^2+12x)/(9x^2-12x+4) is x 2/3

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domain of f(x)=(8x^2+12x)/(9x^2-12x+4)

domain

f (x) = \frac{8 x ^{2} + 12 x}{9 x ^{2} - 12 x + 4}

x < \frac{2}{3} or x > \frac{2}{3}

Interval Notation

(- \infty, \frac{2}{3}) \cup (\frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{2}{3}

The function domain

x < \frac{2}{3} or x > \frac{2}{3}

g (t) = 2 t - 1

e^{- x} + 2

e^{- x} + 3

f (x) = \frac{( x 5 ^{x} )}{5 ^{(x + 2)} - 1}

f (x) = x^{4} - 8 x^{2} + 17

What is the domain of f(x)=(8x^2+12x)/(9x^2-12x+4) ?
The domain of f(x)=(8x^2+12x)/(9x^2-12x+4) is x< 2/3 \lor x> 2/3