What is the domain of f(x)= 1/(4x+7) ?

The domain of f(x)= 1/(4x+7) is x -7/4

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domain of f(x)= 1/(4x+7)

domain

f (x) = \frac{1}{4 x + 7}

x < - \frac{7}{4} or x > - \frac{7}{4}

Interval Notation

(- \infty, - \frac{7}{4}) \cup (- \frac{7}{4}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{7}{4}

The function domain

x < - \frac{7}{4} or x > - \frac{7}{4}

f (t) = 16 - t^{2}

3 x + 1

(x + 1) ln^{2} (x + 1)

\frac{x ^{3} + 3 x ^{2} + 1}{4 x ( x - 1 ) ^{2}}

f (x) = \frac{3 x}{x - 2}

What is the domain of f(x)= 1/(4x+7) ?
The domain of f(x)= 1/(4x+7) is x<-7/4 \lor x>-7/4