What is the domain of sqrt(2+ln(x)) ?

The domain of sqrt(2+ln(x)) is x>= 1/(e^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(2+ln(x))

domain

2 + ln (x)

x \geq \frac{1}{e ^{2}}

Interval Notation

[\frac{1}{e ^{2}}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{e ^{2}}

The function domain

x \geq \frac{1}{e ^{2}}

lo g_{10} (x - 5) + 1

f (x) = \frac{1}{x} + ln (x)

f (x) = \frac{8 x}{9 - 2 x}

f (x) = \frac{x}{x ^{2} + 3 x + 5}

+ X^{3}

What is the domain of sqrt(2+ln(x)) ?
The domain of sqrt(2+ln(x)) is x>= 1/(e^2)