What is the domain of f(x)=4-sqrt(x^2-4x) ?

The domain of f(x)=4-sqrt(x^2-4x) is x = 4

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domain of f(x)=4-sqrt(x^2-4x)

domain

f (x) = 4 - x^{2} - 4 x

x \leq 0 or x \geq 4

Interval Notation

(- \infty, 0] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 4

The function domain

x \leq 0 or x \geq 4

\frac{( 4 x ^{2} + 17 x - 15 )}{( x ^{3} )}

x^{2} = y - 1

f (x) = \frac{x ^{3}}{1 - x}

f (x) = \frac{1}{4 x - 3}

f (x) = 5 + x

What is the domain of f(x)=4-sqrt(x^2-4x) ?
The domain of f(x)=4-sqrt(x^2-4x) is x<= 0\lor x>= 4