What is the critical f(x)=x^3-7x^2+2 ?

The critical f(x)=x^3-7x^2+2 is x=0,x= 14/3

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critical f(x)=x^3-7x^2+2

critical points

f (x) = x^{3} - 7 x^{2} + 2

x = 0, x = \frac{14}{3}

Solution steps

x^{3} - 7 x^{2} + 2

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{14}{3}

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 7 x^{2} + 2 : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{14}{3}

f (x) = x^{2} + 5

y^{4} = x^{3} + 6

f (x) = x + 1

e^{8 x} (3 - x)

What is the critical f(x)=x^3-7x^2+2 ?
The critical f(x)=x^3-7x^2+2 is x=0,x= 14/3