What is the domain of y=4+5/(1+sqrt(x-3)) ?

The domain of y=4+5/(1+sqrt(x-3)) is x>= 3

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domain of y=4+5/(1+sqrt(x-3))

domain

y = 4 + \frac{5}{1 + x - 3}

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

y = \frac{2}{x + 3}

f (x) = 5 (x^{2} - 20)

∣ x - 4 ∣

f (x) = - 5 lo g_{10} (x - 2)

f (x) = ln (x^{2} - 6 x)

What is the domain of y=4+5/(1+sqrt(x-3)) ?
The domain of y=4+5/(1+sqrt(x-3)) is x>= 3