What is the domain of f(x)=(2x^2+x-6)/(sqrt(x+2)) ?

The domain of f(x)=(2x^2+x-6)/(sqrt(x+2)) is x>-2

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domain of f(x)=(2x^2+x-6)/(sqrt(x+2))

domain

f (x) = \frac{2 x ^{2} + x - 6}{x + 2}

x > - 2

Interval Notation

(- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = - 2

Combine real regions and undefined points for final function domain

x > - 2

U (d) = - 0.33 d^{2} + 7 d + 30

f (x) = \frac{1}{tan ^{2} ( x ) - 3}

y = x^{2} (x + 1)^{3} (x - 3)

\frac{1 - 9 4 - x ^{2}}{∣ x - 2 ∣ - ∣ x + 2 ∣}

g (x) = x - 2 x - 3

What is the domain of f(x)=(2x^2+x-6)/(sqrt(x+2)) ?
The domain of f(x)=(2x^2+x-6)/(sqrt(x+2)) is x>-2