What is the domain of f(x)= 3/(x^2-4x-12) ?

The domain of f(x)= 3/(x^2-4x-12) is x 6

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domain of f(x)= 3/(x^2-4x-12)

domain

f (x) = \frac{3}{x ^{2} - 4 x - 12}

x < - 2 or - 2 < x < 6 or x > 6

Interval Notation

(- \infty, - 2) \cup (- 2, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 2

The function domain

x < - 2 or - 2 < x < 6 or x > 6

\frac{x + 2}{2 x + 1}

f (x) = \frac{1}{( x - 3 ) ( 3 x + 1 )}

f (x) = \frac{3 x + 4}{( x + 4 ) ( x + 3 )}

f (x, y) = \frac{1}{x}

What is the domain of f(x)= 3/(x^2-4x-12) ?
The domain of f(x)= 3/(x^2-4x-12) is x<-2\lor-2<x<6\lor x>6