What is the inverse of f(x)=\sqrt[5]{x-8}+3 ?

The inverse of f(x)=\sqrt[5]{x-8}+3 is x^5-15x^4+90x^3-270x^2+405x-235

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[5]{x-8}+3

inverse

x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 235

Solution steps

Replace

x

with

y

Solve for

x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 235

f (x) = 1 - 2^{x}

f (x) = x^{3} + 2

y = x^{2} (x^{2} - 9)^{\frac{1}{2}}

f (x) = 16 - x^{8}

What is the inverse of f(x)=\sqrt[5]{x-8}+3 ?
The inverse of f(x)=\sqrt[5]{x-8}+3 is x^5-15x^4+90x^3-270x^2+405x-235