What is the domain of g(x)=sqrt(x^2-4) ?

The domain of g(x)=sqrt(x^2-4) is x = 2

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domain of g(x)=sqrt(x^2-4)

domain

g (x) = x^{2} - 4

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

f (x) = \frac{1}{x} + \frac{x}{2} + 1

f (x) = \frac{x + 1}{x ^{3} - 9 x}

f (x) = \frac{x}{1 - ln ( x - 3 )}

f (x) = \frac{3}{2 x - 8}

f (x) = \frac{( x + 2 )}{( x ^{2} - 1 )}

What is the domain of g(x)=sqrt(x^2-4) ?
The domain of g(x)=sqrt(x^2-4) is x<=-2\lor x>= 2