What is the domain of 1/(sqrt(x^2+4)) ?

The domain of 1/(sqrt(x^2+4)) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of 1/(sqrt(x^2+4))

domain

\frac{1}{x ^{2} + 4}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{3 x - 4}{7}

y = \frac{3}{x + 2}

f (x) = ln (\frac{x + 3}{x - 3})

f (x) = \frac{x + 1}{2 x - 4}

f (x) = \frac{1}{x ^{2} - 2 x + 1}

What is the domain of 1/(sqrt(x^2+4)) ?
The domain of 1/(sqrt(x^2+4)) is -infinity <x<infinity