What is the domain of f(x)=ln(2-x-x^2) ?

The domain of f(x)=ln(2-x-x^2) is -2<x<1

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domain of f(x)=ln(2-x-x^2)

domain

f (x) = ln (2 - x - x^{2})

- 2 < x < 1

Interval Notation

(- 2, 1)

Solution steps

Find positive values for logs:

- 2 < x < 1

The function domain

- 2 < x < 1

f (x) = ln^{\frac{1}{x}} (x)

f (x) = - 3 - 2 (x - 3) + 4

e^{x - 3}

f (x) = - 6 x + 36

\frac{1 - 2 x}{x ^{2} - 9}

What is the domain of f(x)=ln(2-x-x^2) ?
The domain of f(x)=ln(2-x-x^2) is -2<x<1