What is the domain of f(x)=(x+1)^{1/x} ?

The domain of f(x)=(x+1)^{1/x} is -1 0

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domain of f(x)=(x+1)^{1/x}

domain

f (x) = (x + 1)^{\frac{1}{x}}

- 1 < x < 0 or x > 0

Interval Notation

(- 1, 0) \cup (0, \infty)

Solution steps

Check exponents domain:

x > - 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 < x < 0 or x > 0

6 x - 12

y = 5^{x}

f (x) = \frac{x ^{3}}{( x - 2 ) ^{2}}

\frac{4 x}{5 x - 7}

h (x) = 6 x + 5 x - 3

What is the domain of f(x)=(x+1)^{1/x} ?
The domain of f(x)=(x+1)^{1/x} is -1<x<0\lor x>0