What is the domain of sqrt(2x+2)+sqrt(6-4x) ?

The domain of sqrt(2x+2)+sqrt(6-4x) is -1<= x<= 3/2

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domain of sqrt(2x+2)+sqrt(6-4x)

domain

2 x + 2 + 6 - 4 x

- 1 \leq x \leq \frac{3}{2}

Interval Notation

[- 1, \frac{3}{2}]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq \frac{3}{2}

The function domain

- 1 \leq x \leq \frac{3}{2}

y = 3 - \frac{1}{x}

h (x) = x^{3} + 2 x + 5

f (x) = \frac{3}{x - 9}

f (x) = 2 x^{2} + 4 x - 1

f (x) = 2 x^{2} - 8 x + 5

What is the domain of sqrt(2x+2)+sqrt(6-4x) ?
The domain of sqrt(2x+2)+sqrt(6-4x) is -1<= x<= 3/2