What is the domain of y=sqrt(x/(x-1)) ?

The domain of y=sqrt(x/(x-1)) is x 1

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domain of y=sqrt(x/(x-1))

domain

y = \frac{x}{x - 1}

x \leq 0 or x > 1

Interval Notation

(- \infty, 0] \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x \leq 0 or x > 1

4 x^{2} + 17 x - 15

f (x) = \frac{x - 2}{x + 1 - 2}

f (x) = \frac{1}{2} ln (3 - x^{2})

\frac{x ^{2} - 2 x}{x - 6}

x^{2} 3 x - 5

What is the domain of y=sqrt(x/(x-1)) ?
The domain of y=sqrt(x/(x-1)) is x<= 0\lor x>1