What is the domain of f(x)=sqrt(-x^2+7x-12) ?

The domain of f(x)=sqrt(-x^2+7x-12) is 3<= x<= 4

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domain of f(x)=sqrt(-x^2+7x-12)

domain

f (x) = - x^{2} + 7 x - 12

3 \leq x \leq 4

Interval Notation

[3, 4]

Solution steps

Find non-negative values for radicals:

3 \leq x \leq 4

The function domain

3 \leq x \leq 4

\frac{- 2 x + 4}{x - 6}

x^{3}

g (x) = 3

f (x) = (x^{2} - 6 x + 5) y^{2} = 4 y - 1

(x - 1) (x - 4)

What is the domain of f(x)=sqrt(-x^2+7x-12) ?
The domain of f(x)=sqrt(-x^2+7x-12) is 3<= x<= 4