What is the domain of y=sqrt(x^2-4x) ?

The domain of y=sqrt(x^2-4x) is x = 4

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domain of y=sqrt(x^2-4x)

domain

y = x^{2} - 4 x

x \leq 0 or x \geq 4

Interval Notation

(- \infty, 0] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 4

The function domain

x \leq 0 or x \geq 4

f (x) = \frac{ln ( 4 x )}{x}

f (x) = 2 x^{3} - 50 x

f (x) = \frac{- 4 x}{x ^{2} + 2}

f (x) = 3 x^{2} - 2 x

f (x) = \frac{x}{x - 6}

What is the domain of y=sqrt(x^2-4x) ?
The domain of y=sqrt(x^2-4x) is x<= 0\lor x>= 4