What is the domain of ((x^3))/((4x^2+17x-15)) ?

The domain of ((x^3))/((4x^2+17x-15)) is x 3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of ((x^3))/((4x^2+17x-15))

domain

\frac{( x ^{3} )}{( 4 x ^{2} + 17 x - 15 )}

x < - 5 or - 5 < x < \frac{3}{4} or x > \frac{3}{4}

Interval Notation

(- \infty, - 5) \cup (- 5, \frac{3}{4}) \cup (\frac{3}{4}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{4}, x = - 5

The function domain

x < - 5 or - 5 < x < \frac{3}{4} or x > \frac{3}{4}

f (x) = \frac{7}{3 - 6 x}

f (x) = \frac{2 x ^{3}}{x ^{2} - 4}

f (x) = x - 36

\frac{2 x - 6}{x + 3}

y = - x^{2} - 8

What is the domain of ((x^3))/((4x^2+17x-15)) ?
The domain of ((x^3))/((4x^2+17x-15)) is x<-5\lor-5<x< 3/4 \lor x> 3/4