What is the domain of 2/(\frac{1){x-2}+3} ?

The domain of 2/(\frac{1){x-2}+3} is x 2

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domain of 2/(\frac{1){x-2}+3}

domain

\frac{2}{\frac{1}{x - 2} + 3}

x < \frac{5}{3} or \frac{5}{3} < x < 2 or x > 2

Interval Notation

(- \infty, \frac{5}{3}) \cup (\frac{5}{3}, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{5}{3}, x = 2

The function domain

x < \frac{5}{3} or \frac{5}{3} < x < 2 or x > 2

g (x) = \frac{7 x}{x ^{2} - 4}

\frac{3}{4} x + 2

y = \frac{x + 9}{x ^{2} - 81}

y = arcsin (\frac{1}{x})

f (t) = 4 - x

What is the domain of 2/(\frac{1){x-2}+3} ?
The domain of 2/(\frac{1){x-2}+3} is x< 5/3 \lor 5/3 <x<2\lor x>2