What is the domain of f(x)= 1/5 x^3-sqrt(x^2+1) ?

The domain of f(x)= 1/5 x^3-sqrt(x^2+1) is -infinity <x<infinity

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domain of f(x)= 1/5 x^3-sqrt(x^2+1)

domain

f (x) = \frac{1}{5} x^{3} - x^{2} + 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

lo g_{e} (x^{2} - 1)

f (x) = 4 (x - 12) (x - 7)

∣ 2 x ∣ - 2

f (x) = x^{2} + 3 x - x

f (x) = 121 - t^{2}

What is the domain of f(x)= 1/5 x^3-sqrt(x^2+1) ?
The domain of f(x)= 1/5 x^3-sqrt(x^2+1) is -infinity <x<infinity