What is the domain of (3sqrt(x^2-9))/(x-1) ?

The domain of (3sqrt(x^2-9))/(x-1) is x = 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (3sqrt(x^2-9))/(x-1)

domain

\frac{3 x ^{2} - 9}{x - 1}

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x \leq - 3 or x \geq 3

f (x) = ∣ x + 2 ∣ - 1, - 4 < x < 0

f (x) = 3 x^{2} + 6 - 4

f (x) = 2 + lo g_{2} (x)

f (x) = 4 x + 7

y = \frac{4}{x - 2}

What is the domain of (3sqrt(x^2-9))/(x-1) ?
The domain of (3sqrt(x^2-9))/(x-1) is x<=-3\lor x>= 3