What is the domain of f(x)=ln(10x-5) ?

The domain of f(x)=ln(10x-5) is x> 1/2

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domain of f(x)=ln(10x-5)

domain

f (x) = ln (10 x - 5)

x > \frac{1}{2}

Interval Notation

(\frac{1}{2}, \infty)

Solution steps

Find positive values for logs:

x > \frac{1}{2}

The function domain

x > \frac{1}{2}

- x^{2} + x + 12

f (x) = 20 x + 5

f (x) = x^{2} - 4 x + (x^{2} - 3 x + 2)

f (x) = \frac{ln ( x - 1 )}{x - 3 + 2 x}

\frac{ln ( x )}{ln ( 3 )}