What is the domain of y= 1/(1+sqrt(x)) ?

The domain of y= 1/(1+sqrt(x)) is x>= 0

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domain of y= 1/(1+sqrt(x))

domain

y = \frac{1}{1 + x}

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

ln (2 x + 3)

8 ln (x) + 56

y = \frac{x ^{2} + 3 x - 4}{6 - x - x ^{2}}

f (x) = - 8 + \frac{1}{2} x

f (x) = 2 x - 3 + 5

What is the domain of y= 1/(1+sqrt(x)) ?
The domain of y= 1/(1+sqrt(x)) is x>= 0