What is the domain of f(x)= 1/(x^2+3x-4) ?

The domain of f(x)= 1/(x^2+3x-4) is x 1

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domain of f(x)= 1/(x^2+3x-4)

domain

f (x) = \frac{1}{x ^{2} + 3 x - 4}

x < - 4 or - 4 < x < 1 or x > 1

Interval Notation

(- \infty, - 4) \cup (- 4, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 4

The function domain

x < - 4 or - 4 < x < 1 or x > 1

f (x) = \frac{x}{1 - x}

y = arccos (3 - 2 x)

\frac{1}{- x ^{2} + 5 x}

f (x) = ln (x^{2} + 16)

f (x) = x^{3} + x^{2} - 3 x + 1

What is the domain of f(x)= 1/(x^2+3x-4) ?
The domain of f(x)= 1/(x^2+3x-4) is x<-4\lor-4<x<1\lor x>1