What is the domain of f(x)=sqrt(4-x)+sqrt(2x+0.8) ?

The domain of f(x)=sqrt(4-x)+sqrt(2x+0.8) is -0.4<= x<= 4

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domain of f(x)=sqrt(4-x)+sqrt(2x+0.8)

domain

f (x) = 4 - x + 2 x + 0.8

- 0.4 \leq x \leq 4

Interval Notation

[- 0.4, 4]

Solution steps

Find non-negative values for radicals:

- 0.4 \leq x \leq 4

The function domain

- 0.4 \leq x \leq 4

y = (lo g_{5} (x)) + 2

f (x) = lo g_{10} (\frac{x - 3}{3 x})

f (x) = \frac{x ^{2} + 7 x + 2}{x + 2}

x^{2} - 7 x - 8

x^{6} + 2 x^{5} + 7 x^{2}

What is the domain of f(x)=sqrt(4-x)+sqrt(2x+0.8) ?
The domain of f(x)=sqrt(4-x)+sqrt(2x+0.8) is -0.4<= x<= 4