What is the domain of f(x)=ln(x^2-4x+3) ?

The domain of f(x)=ln(x^2-4x+3) is x 3

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domain of f(x)=ln(x^2-4x+3)

domain

f (x) = ln (x^{2} - 4 x + 3)

x < 1 or x > 3

Interval Notation

(- \infty, 1) \cup (3, \infty)

Solution steps

Find positive values for logs:

x < 1 or x > 3

The function domain

x < 1 or x > 3

f (x) = 4 tan (2 x + \frac{π}{3}) - 1

f (x) = \frac{3 - x}{x + 5}

\frac{2}{x ^{2} - 2 x - 3}

\frac{2 x + 7}{x + 2}

f (x) = \frac{5}{x - 4} + x^{2} - 9

What is the domain of f(x)=ln(x^2-4x+3) ?
The domain of f(x)=ln(x^2-4x+3) is x<1\lor x>3