What is the domain of f(x)=sqrt(4\sqrt{24-2x-x^2)} ?

The domain of f(x)=sqrt(4\sqrt{24-2x-x^2)} is -6<= x<= 4

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domain of f(x)=sqrt(4\sqrt{24-2x-x^2)}

domain

f (x) = 4 24 - 2 x - x^{2}

- 6 \leq x \leq 4

Interval Notation

[- 6, 4]

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 4

The function domain

- 6 \leq x \leq 4

lo g_{3} (x + 4)

f (x) = lo g_{\frac{1}{4}} (x)

\frac{1}{2} x + π

f (x) = x - 5 + 2

f (x) = \frac{7 x}{9 x - 1}

What is the domain of f(x)=sqrt(4\sqrt{24-2x-x^2)} ?
The domain of f(x)=sqrt(4\sqrt{24-2x-x^2)} is -6<= x<= 4