What is the domain of y=sqrt(sin(2x)) ?

The domain of y=sqrt(sin(2x)) is pin<= x<= pi/2+pin

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domain of y=sqrt(sin(2x))

domain

y = sin (2 x)

πn \leq x \leq \frac{π}{2} + πn

Interval Notation

[πn, \frac{π}{2} + πn]

Solution steps

Find non-negative values for radicals:

πn \leq x \leq \frac{π}{2} + πn

The function domain

πn \leq x \leq \frac{π}{2} + πn

f (x) = \frac{x + 5}{x ^{2} + 5 x + 6}

[- 2.2]

f (x) = x^{3} - 10 x^{2} + 16 x

f (x) = \frac{x + 1}{x ^{2} - 7 x + 12}

f (x) = \frac{9}{x - 7}

What is the domain of y=sqrt(sin(2x)) ?
The domain of y=sqrt(sin(2x)) is pin<= x<= pi/2+pin