What is the domain of f(x)= 9/(sqrt(x-7)) ?

The domain of f(x)= 9/(sqrt(x-7)) is x>7

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domain of f(x)= 9/(sqrt(x-7))

domain

f (x) = \frac{9}{x - 7}

x > 7

Interval Notation

(7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 7

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

x > 7

f (x) = 2 x^{2} - 4 x - 3

f (x) = \frac{1}{x - 1} - 3

f (x) = 2 - x + 2

y = - 1, x \geq 0

4 x - 6, x \neq = 1

What is the domain of f(x)= 9/(sqrt(x-7)) ?
The domain of f(x)= 9/(sqrt(x-7)) is x>7