What is the domain of 1/(sqrt(x-9)) ?

The domain of 1/(sqrt(x-9)) is x>9

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domain of 1/(sqrt(x-9))

domain

\frac{1}{x - 9}

x > 9

Interval Notation

(9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 9

Find undefined (singularity) points:

x = 9

Combine real regions and undefined points for final function domain

x > 9

f (x) = x^{3} - 3 x^{2} + 1

\frac{2 x ^{2}}{6 x ^{2} - x - 2}

x^{9} - 6 x^{4} + 9

f (x) = 3 x + 24

y = \frac{7 x ^{2} - 63}{4}