What is the domain of f(x)= 1/(8x+64) ?

The domain of f(x)= 1/(8x+64) is x -8

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domain of f(x)= 1/(8x+64)

domain

f (x) = \frac{1}{8 x + 64}

x < - 8 or x > - 8

Interval Notation

(- \infty, - 8) \cup (- 8, \infty)

Solution steps

Find undefined (singularity) points:

x = - 8

The function domain

x < - 8 or x > - 8

\frac{2 x}{3 x - 8}

\frac{2 x}{3 x - 6}

f (x) = \frac{x + 1}{x ^{2} - 16}

f (x) = \frac{- 1}{2 x x}

\frac{1 + x ^{2}}{1 - x ^{2}}

What is the domain of f(x)= 1/(8x+64) ?
The domain of f(x)= 1/(8x+64) is x<-8\lor x>-8