What is the domain of f(x)= 1/(x^2)-3 ?

The domain of f(x)= 1/(x^2)-3 is x 0

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domain of f(x)= 1/(x^2)-3

domain

f (x) = \frac{1}{x ^{2}} - 3

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

f (x) = \frac{1}{x ^{2}} + 1

f (x) = \frac{2 x + 1}{x + 2}

f (x) = 2 (2)^{x + 4} - 1

x^{2} + 7, x \geq - 5

\frac{2 x - 6}{x ^{2} - 6 x}

What is the domain of f(x)= 1/(x^2)-3 ?
The domain of f(x)= 1/(x^2)-3 is x<0\lor x>0