What is the domain of f(x)=(x-7)/(3x^2-4x+1) ?

The domain of f(x)=(x-7)/(3x^2-4x+1) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x-7)/(3x^2-4x+1)

domain

f (x) = \frac{x - 7}{3 x ^{2} - 4 x + 1}

x < \frac{1}{3} or \frac{1}{3} < x < 1 or x > 1

Interval Notation

(- \infty, \frac{1}{3}) \cup (\frac{1}{3}, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = \frac{1}{3}

The function domain

x < \frac{1}{3} or \frac{1}{3} < x < 1 or x > 1

lo g_{10} (x^{2} - 2 x - 15)

2 x - 4

\frac{x + 5}{x - 7}

x^{35}

y = ln (x^{2} - 14 x)

What is the domain of f(x)=(x-7)/(3x^2-4x+1) ?
The domain of f(x)=(x-7)/(3x^2-4x+1) is x< 1/3 \lor 1/3 <x<1\lor x>1