What is the domain of ln(x+sqrt(x^2+1)) ?

The domain of ln(x+sqrt(x^2+1)) is -infinity <x<infinity

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domain of ln(x+sqrt(x^2+1))

domain

ln (x + x^{2} + 1)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = arccos (\frac{x}{2}) - \frac{π}{2}

f (x) = \frac{4}{x + 1} + 3

f (x) = (x - 3) (x + 2)

f (x) = ln (3 - x^{2})

y = \frac{x}{x}

What is the domain of ln(x+sqrt(x^2+1)) ?
The domain of ln(x+sqrt(x^2+1)) is -infinity <x<infinity